prototype property of class methods in JavaScript

Question

class C { foo() {} }
C.prototype.foo // function foo() {}
C.prototype.foo.prototype // undefined - why?

Why is the .prototype property of class methods not set when created via the class method syntax?

Because JavaScript attempts to hide/cover-up the power of prototypal inheritance while not providing true classical inheritance with the class keyword. It's the worst of both worlds, tbh. — mhodges
– mhodges, Commented May 22, 2017 at 15:47
I expect it to be an object per a normal function declaration (I think). — Ben Aston
– Ben Aston, Commented May 22, 2017 at 15:47

Bergi · Accepted Answer · 2017-05-22 16:01:58Z

3

Because methods (like arrow functions) are no constructors, and don't need a .prototype from which the prototype of instances would be initialised, none will get created.

This is a new feature in ES6, which distinguishes method definitions in object literals and class definitions from usual function definitions.

answered May 22, 2017 at 16:01

Bergi

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