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I need to delete a list from a list of lists based off a second list. I have the following:

LA = []
LA.append([u'02fc0b', u'val1', u'val2'])
LA.append([u'0a1ac', u'val1', u'val2'])
LA.append([u'02fc0b', u'val1', u'val2'])
LA.append([u'safsdf', u'val1', u'val2'])
LA.append([u'lmuylj', u'val1', u'val2'])


EXCL = []
EXCL.append('02fc0b')
EXCL.append('safsdf')

And I'd like to exclude any list in LA[] where the value in position 0 appears in EXCL[]. I can totally do this with a loop, but I feel like there is a more Pythonic approach to use, and I'd love to learn.

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  • 2
    result = [x for x in LA if x[0] not in EXCL] Commented May 22, 2017 at 19:13
  • A loop is totally pythonic Commented May 22, 2017 at 19:24
  • can you help me define pythonic? Commented May 22, 2017 at 19:44

1 Answer 1

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4

you could use filter with custom condition:

LA = []
LA.append([u'02fc0b', u'val1', u'val2'])
LA.append([u'0a1ac', u'val1', u'val2'])
LA.append([u'02fc0b', u'val1', u'val2'])
LA.append([u'safsdf', u'val1', u'val2'])
LA.append([u'lmuylj', u'val1', u'val2'])


EXCL = []
EXCL.append('02fc0b')
EXCL.append('safsdf')

d = set(EXCL)
print(list(filter(lambda v: v[0] not in d, LA)))
#[['0a1ac', 'val1', 'val2'], ['lmuylj', 'val1', 'val2']]
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