Why does in_array() always return false?

Question

Try this code:

You use the URL with the parameter id e.g index.php?id=value This value will be pushed into the data array that is maintained within a session.

I expect this test to always return true. But it always returns false, why?

   if (in_array($id, $_SESSION['data'])) {
        echo "$id in array";
    } else {
        echo "$id not in array";
    }

The full code:

<?php

    session_start();

     //uncomment when need to clear the data array.
    //if (isset($_SESSION['data'])) {
    //    unset($_SESSION['data']);
    //    die;
    //}

    if (!isset($_SESSION['data'])) {
        $_SESSION['data'] = [];
    }
    if (isset($_GET['id'])) {
        $id = strval($_GET['id']);

        if (!in_array($id, $_SESSION['data'])) {
            $_SESSION['data'][$id] = "data_$id";
        }

        echo '<pre>';
        print_r($_SESSION['data']);
        echo '</pre>';

        // Why does this always return false?
        if (in_array($id, $_SESSION['data'])) {
            echo "$id in array";
        } else {
            echo "$id not in array";
        }
    }?>

@JonStirling Opps.. then I need to use array_key_exists instead - Thanks — Saleh Rezq
– Saleh Rezq, Commented May 23, 2017 at 13:08

shubham715 · Accepted Answer · 2017-05-23 12:58:06Z

1

Try isset() function.

Example:-

if (isset($_SESSION['data'][$id])) {
  echo "$id in array";
} else {
  echo "$id not in array";
}

answered May 23, 2017 at 12:58

shubham715

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