I have an if statement in my bash script as follows:
if [[ eb status my-env-staging-worker | grep 'Green' -ne 0 ] || [ eb status my-env-staging-web | grep 'Green' -ne 0 ]]
Basically if the first or second eb status command dont have the string Green I'd like to execute some other stuff.
However I get the following Error:
Conditional binary operator expected syntax error near status script returned exit code 2
Could you tell me whats wrong?
[[ and [ are not for grouping. They're independent commands. Instead of if [[ cmd1 -ne 0 ] || [ cmd2 -ne 0 ]], leave out the brackets and the tests and simply write if cmd1 || cmd2.
if eb status my-env-staging-worker | grep -q 'Green' || eb status my-env-staging-web | grep -q 'Green'
I've added -q to suppress grep's output since you only care about the return code.
If you want to invert the condition, write:
if ! eb status my-env-staging-worker | grep -q 'Green' && ! eb status my-env-staging-web | grep -q 'Green'
or
if ! { eb status my-env-staging-worker | grep -q 'Green' || eb status my-env-staging-web | grep -q 'Green'; }
Here you can see { and } used for grouping. Curly braces and parentheses are bash's grouping tokens.
! are needed.! cmd1 || ! cmd2.