How to write a shell script that will add two numbers?

Question

Assuming that the inputs are given as command line arguments and if two numbers are not given show a error message as "command line arguments are missing".

Sample output:

addition of 1 and 2 is 3.

echo "Enter two numbers" read num1 num2 sum=expr $num1 + $num2 echo "the sum of $num1 and $num2 is $sum" — Jay
– Jay, Commented May 26, 2017 at 7:42

tso · Accepted Answer · 2017-05-26 20:02:13Z

3

#!/bin/bash
if [ $# -lt 2 ]
then
    echo "command line arguments are missing "
else
    echo $(($1+$2))
fi

edited May 26, 2017 at 20:02

answered May 26, 2017 at 7:39

tso

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1 Comment

chepner Over a year ago

$[...] is an obsolete bash extension. It should never be used anywhere.

justaguy · Accepted Answer · 2017-05-26 11:42:04Z

3

In awk:

echo 5 5 | awk  '{ print $1 + $2}'
10

answered May 26, 2017 at 11:42

justaguy

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Comments

Sagar Jadhav · Accepted Answer · 2018-07-12 12:33:04Z

2

actualNumber=720; incrementNo=1;

actualNumber=$(expr "$actualNumber" + "$incrementNo");

echo $actualNumber

answered Jul 12, 2018 at 12:33

Sagar Jadhav

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Comments

Harini · Accepted Answer · 2017-05-28 05:43:58Z

0

DESCRIPTION: This script will read two integer value from users and give output as sum of two values SCRIPT:

#!/bin/bash

echo -n "Enter the first number : "
read num1
echo -n "Enter the second number : "
read num2
sum=`expr $num1 + $num2`
echo "sum of two value is $sum"

RUN:

sh sum.sh

answered May 28, 2017 at 5:43

Harini

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Comments

samar ranjan Nayak · Accepted Answer · 2020-09-20 18:59:20Z

0

Just to put all in one place.

num1=10 
num2=20 
 
sum=$(( $num1 + $num2 )) 
 
sum=`expr $num1 + $num2` 
 
sum=$[num1+num2] 
 
sum=$(echo $num1 $num2 | awk '{print $1 + $2}') 
 
sum=$(expr $num1 + $num2) 
 
sum=$(expr "$num1" + "$num2")

answered Sep 20, 2020 at 18:59

samar ranjan Nayak

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