Python handling exceptions

Question

In my program, I want to take in an input which should be a number.If the user inputs a string, however, the program returns an exception.I want the program set in such a way that the input is converted to int and then if the string is anything other than an int the program prints that "Stop writing please".Like for example:

   x=input("Enter a number")
        if int(x)=?:         #This line should check whether the integer conversion is possible
        print("YES")
        else                #This line should execute if the above conversion couldn't take place
        print("Stop writing stuff")

Irfan434 · Accepted Answer · 2017-06-05 06:01:35Z

2

You'll need to use try-except blocks:

x=input("Enter a number")
try:
    x = int(x)    # If the int conversion fails, the program jumps to the exception
    print("YES")  # In that case, this line will not be reached
except ValueError:
    print("Stop writing stuff")

edited Jun 5, 2017 at 6:01

answered Jun 5, 2017 at 5:55

Irfan434

1,71115 silver badges21 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

John Dengis · Accepted Answer · 2017-06-05 05:56:43Z

0

You can simply use a try-except block to catch the exceptional case, and inside there, print your statement. Something like this:

x=input("Enter a number")
try:
    x=int(x)
    print("YES") 
except: 
    print("Stop writing stuff")

answered Jun 5, 2017 at 5:56

John Dengis

1922 silver badges8 bronze badges

Collectives™ on Stack Overflow

Python handling exceptions

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related