XSTREAM array converter

Question

I want to convert below XML to objects. I

<authentication>
    <name>Reese Rideout</name>
    <shows type="array">
        <show>stage</show>
        <show>youtube</show>
    </shows>
</authentication>

I have Authentication class with List<Show> shows. I believe I will need to use the array converter. However, I do not understand how to use it and am not finding any documents.

Kindly suggest how could I parse this into my object graph.

djangofan · Accepted Answer · 2013-12-05 23:52:34Z

3

This is how I fixed this:

xstream.alias("shows", Shows.class);
xstream.alias("show", String.class);

And also set the Shows.shows field as an implicit collection: xstream.addImplicitCollection(Shows.class, "shows");

edited Dec 5, 2013 at 23:52

djangofan

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answered Dec 14, 2010 at 14:15

Jinesh Parekh

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1 Comment

djangofan Over a year ago

I'm not totally understanding your answer. Can you give more detail like Jigar Joshi did? What is the context of using .addImplicitCollection ?

Jigar Joshi · Accepted Answer · 2010-12-14 06:30:24Z

2

For

 <authentication>
      <name>Reese Rideout</name>
      <shows type="array">
         <show>stage</show>
         <show>youtube</show>
       </shows>
    </authenticatoin>

you can have

class Authentication{
String name;
List<Show> shows;
}

class Show{
List<String> show;
}

You will have to use aliasing

xstream.alias("authentication", Authentication.class);
xstream.alias("Show", Show.class);

edited Dec 14, 2010 at 6:30

answered Dec 14, 2010 at 6:07

Jigar Joshi

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3 Comments

Jigar Joshi Over a year ago

@Jinesh it can be , but from the XML you have given there is no need to take it as Object , String will do it for you

Jinesh Parekh Over a year ago

That did not work. the alias that i am configuring is xstream.aliasField("show", Show.class, "show");

Jinesh Parekh Over a year ago

com.thoughtworks.xstream.converters.ConversionException: show : show ---- Debugging information ---- message : show : show

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