C# Deserialize XML elements with attributes into List

Question

Here's the XML:

<xml id = "1234">
    <connect id="2"/>
    <connect id="1"/>
    <connect id="21"/>
    <connect id="3"/>
    <connect id="7"/>
</xml>

Currently I am doing this:

public class xml
{
    //Constructor

    [XmlAttribute ("id")]
    public uint id;

    [XmlElement ("connect")]
    public List<Connection> Connections { get; set; }

    //Deserializer
}

public class Connection
{
    [XmlAttribute ("id")]
    public uint id { get; set; }
}

The goal is to get rid of the Connection class entirely and Deserialize the xml straight into:

List<uint> connections;

Ofir Winegarten · Accepted Answer · 2018-12-23 09:22:22Z

1

~~First, your XML is not valid, i guess it's just a typo - there no end tag for "connect".~~

I recommend you to use linq XDocument.
Then it's easy:

XDocument xdoc = XDocument.Parse(xml);
List<uint> list = xdoc
                    .Descendants("connect")
                    .Select(node => uint.Parse(node.Attribute("id").Value))
                    .ToList();

edited Dec 23, 2018 at 9:22

answered Jun 6, 2017 at 18:50

Ofir Winegarten

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4 Comments

user7811169 Over a year ago

Is there a way to achieve this using System.Xml.Serialization?

Jonathan Hansen Over a year ago

Thanks! This was exactly the solution I was looking for. I didn't realize the potential of XDocument.

da_berni Over a year ago

<connect /> is self closing. why shouldn't it be valid then?

Ofir Winegarten Over a year ago

@da_berni, the question was edited and fixed after i've posted that

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