PHP preg_replace modification

Question

I have an expression [text][id] which should be replaced with a link <a href='id'>text</a>

The solution is (id is integer)

$s = preg_replace("/\[([^\]]+)(\]*)\]\[([0-9]+)\]/","<a href='$3'>$1$2</a>",$string);

However, in some cases (not always!) the expression may be as the following

[text][id][type]

which should in this case be replaced with <a href='id' class='type'>text</a>

Ideas?

There are no numbers in your example what is \[([0-9]+)\] doing? or id is an integer? — chris85
– chris85, Commented Jun 11, 2017 at 21:53
What are text and type? I think you are going to need 2 regex for this because the replacement is going to need have class="$3" everytime, or I guess you could strip it in another step, if empty. — chris85
– chris85, Commented Jun 11, 2017 at 21:57

RomanPerekhrest · Accepted Answer · 2017-06-11 22:15:05Z

5

The solution using preg_replace_callback function:

$str = 'some text [hello][1] some text [there][2][news]';  // exemplary string

$result = preg_replace_callback('/\[([^][]+)\]\[([^][]+)\](?:\[([^][]+)\])?/',function($m){
    $cls = (isset($m[3]))? " class='{$m[3]}'" : "";  // considering `class` attribute
    return "<a href='{$m[2]}'$cls>{$m[1]}</a>";
},$str);

print_r($result);

The output (as web page source code):

some text <a href='1'>hello</a> some text <a href='2' class='news'>there</a>

(?:\[([^][]+)\])? - considering optional 3rd captured group (for class attribute value)

edited Jun 11, 2017 at 22:15

answered Jun 11, 2017 at 22:05

RomanPerekhrest

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