swift UICollectionView section separation without Two-Dimensional Array

Question

Example

// My data to use
let items: [Any] = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 ...]

/*
  // UICollectionView result I want

  <Section [Item1, Item2, Item3]>
  <Other Section A>
  <Section [Item4, Item5, Item6]>
  <Other Section B>
  <Section [Item7, Item8, Item9]>
  <Other Section A>
  <Section [Item10, Item11, Item12]>
  <Other Section B>
*/

If my data is a Two-Dimensional Array like below, I can see the result easier.

let items: [[Any]] = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12] ...]

But I think I should use only One-Dimensional Array.

Because my items will add/remove frequently. and need API Communication.. and need LoadMore function.. Maybe these things become complicated if use 2d array. and this problem relate other sections' position.

Is it possible only One-Dimensional Array? and my think is correct?

How do you decide which item goes in which section? Is it just three items per section? — overactor
– overactor, Commented Jun 12, 2017 at 10:02

overactor · Accepted Answer · 2017-06-12 11:23:59Z

1

If you have three items in every section, you can simply calculate how many sections and items per section you'll have:

func numberOfSections(in collectionView: UICollectionView) -> Int {
    return items.count / 3 + 1
}

func collectionView(_ collectionView: UICollectionView, numberOfItemsInSection section: Int) -> Int {
    return min(3, items.count - 3 * section)
}

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
    let item = items[indexPath.section * 3 + item]
    // do something with item
}

answered Jun 12, 2017 at 11:23

overactor

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2 Comments

Byoth Over a year ago

Good answer. Thanks!

Byoth Over a year ago

I knew only about vote.. but it is need 15 reputation. so I thought I couldn't do anything yet. thanks to your comment, I know about 'Mark' now. I won't forget it.

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