Show/Hide if php variable it's true

Question

This is my html code:

<div id="view" class="login-box animated fadeInUp"<?php if ($reg===true){?>style="display:none"<?php } ?>>

        </div>

        <div id="popup"<?php if ($reg===false){?>style="display:none"<?php } ?>>
        </div>

This is part of my php code:

<?php
 ob_start();
 session_start();
error_reporting( ~E_DEPRECATED & ~E_NOTICE );

 $conn = mysqli_connect('localhost','root','','slide-uploader');

 if ( !$conn ) {
  die("Connection failed : " . mysqli_connect_error());
 }

 $error = false;
 $reg = false;

 /*Verifico i campi della form*/
 if ( isset($_POST['submit']) ) {


  $email = trim($_POST['user_email']);
  $email = strip_tags($email);
  $email = htmlspecialchars($email);
  $mailValidation = explode('@',$email)[1];
  $matricola = trim($_POST['user_matricola']);
   $name = ucfirst(explode('.',$email)[0]);
   $surname = ucfirst(preg_replace('/[0-9]+/', '', explode('@',explode('.',$email)[1]))[0]);
   $queryS = "SELECT * FROM studente WHERE Matricola ='$matricola'";
   $resS = mysqli_query($conn,$queryS);
   $count = mysqli_num_rows($resS);
   if($count<1){
     $query = "INSERT INTO studente (Matricola, Nome, Cognome, User) VALUES('$matricola','$name','$surname','$email')";
     $res = mysqli_query($conn,$query);
   }else{
     some code...
   }

   if ($res) {
    some code...
    unset($email);
    $reg = true;
    some code...
   } else {
     some code...
   }
  }
 }
ob_end_flush();
?>

I log the user and then return to the previous page (window.history.go (-1)) but $reg does not seem to be set.

As I should do to set the $reg variable in the html page? The html page and the php page are two separate files.

Should I use variable $ _SESSION?

When you say $reg variable in the html page? do you mean a .html file? PHP can't run in a html file. — Andreas
– Andreas, Commented Jun 14, 2017 at 8:40
@Andreas It is actually possible to configure your server to parse .html-files as PHP. But it's not recommended. — StuntHacks
– StuntHacks, Commented Jun 14, 2017 at 8:42
Your code is vulnerable to SQL injection, you need to fix this. — Enstage
– Enstage, Commented Jun 14, 2017 at 8:43
@StuntHacks That sounds like a very strange idea. Can't really see the point of that. I mean you only have to rename the file from .html to .php — Andreas
– Andreas, Commented Jun 14, 2017 at 8:43
@Andreas I know. And I don't know why one would do that. Just wanted to state, that it's indeed possible. — StuntHacks
– StuntHacks, Commented Jun 14, 2017 at 8:44

StuntHacks · Accepted Answer · 2017-06-14 08:42:03Z

0

I wasn't able to fully understand what your website is supposed to do, but if you just want to hide/show html content depending on whether a variable is true or false, you can do that with a logic similar to this:

if ( $var ) //$var is true; display content
{
    ?>
        <div>Your html content that is supposed to be shown</div>
    <?php
}

You can even add an else, to show different content if it is not true.

if ( $var ) //$var is true; display content
{
    ?>
        <div>Your html content that is supposed to be shown</div>
    <?php
}
else
{
    ?>
        <div>A different html content</div>
    <?php
}

answered Jun 14, 2017 at 8:42

StuntHacks

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Comments

Prd · Accepted Answer · 2017-06-14 09:21:02Z

0

I don't know why you have used "display:none" for both true and false situations. You can try "display:block;" if $reg is true (also include a blank space before style in both the places)

<div id="view" class="login-box animated fadeInUp" <?php if ($reg===true){?> style="display:block;"<?php } ?>>

    </div>

<div id="popup"<?php if ($reg===false){?> style="display:none"<?php } ?>>
    </div>

answered Jun 14, 2017 at 9:21

Prd

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