How to find minimum value in an array using ternary operator in swift

Question

let array = [2,3,5,7,3,1,8,9,0,2,4,1]
var minvalue = array[0]
for values in array {
  values < minvalue ? minvalue = values : minvalue
}
print(minvalue)

This is the code i tried , I want the minimum value in the array, If I use if..else I can able to do but cant find using ternary operator.

Nirav D · Accepted Answer · 2017-06-20 07:31:53Z

4

You can use ternary operator this way.

for values in array {
    minvalue = values < minvalue ? values : minvalue
}

But in Swift instead of that simplest option is to use min().

print(array.min())

answered Jun 20, 2017 at 7:31

Nirav D

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Comments

hardikdevios · Accepted Answer · 2017-06-20 07:29:13Z

0

To Get Min value SWIFT 3

array.min()

answered Jun 20, 2017 at 7:29

hardikdevios

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1 Comment

Mohamed Siddique Over a year ago

Hi, I would like to know how to find through looping and ternary operator.

Mina · Accepted Answer · 2017-06-20 07:30:14Z

0

You can do this by sorting the array:

let sortedArray = array.sorted()
var minvalue = sortedArray[0]

answered Jun 20, 2017 at 7:30

Mina

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3 Comments

Rob Over a year ago

Technically correct, but inefficient way to solve the problem.

Mina Over a year ago

why? would you please inform me?

Rob Over a year ago

Sorts find not only the smallest value, but also determine the second smallest value, the third smallest, etc. It's a lot more work than is required if you only need to know what the minimum value was. Even good sort algorithms are, say, O(n log n) complexity. The min function is a trivial scan through the results, with O(n) time and O(1) memory.

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