I have this SQL script tht work properly:
INSERT INTO #XMLwithOpenXML(XMLData, LoadedDateTime)
SELECT CONVERT(XML, BulkColumn) AS BulkColumn, GETDATE()
FROM OPENROWSET(BULK 'C:\temp\test.wordpress.2017-05-22.xml', SINGLE_BLOB) AS x;
SELECT @XML = XMLData FROM #XMLwithOpenXML
Now I need to pass the xml file path with a variable.
How do I have to change the script?
Thanks to support
You can use dynamic SQL:
create table #XMLwithOpenXML(XMLData xml, LoadedDateTime DateTime)
declare @xml xml
declare @filename nvarchar(100)
declare @sql nvarchar(max)
set @filename ='F:\a.xml'
set @sql = 'INSERT INTO #XMLwithOpenXML(XMLData, LoadedDateTime) '
set @sql = @sql +' SELECT CONVERT(XML, BulkColumn) AS BulkColumn, GETDATE() '
set @sql = @sql +' FROM OPENROWSET(BULK ''' + @filename +''', SINGLE_BLOB) AS x;'
EXEC (@Sql)
SELECT @XML = XMLData FROM #XMLwithOpenXML
SELECT @XML
drop table #XMLwithOpenXML
