XSLT: contains() function with multiple strings

Question

I've got an XML in this vein:

<style name='Danger'/>
<style name='Danger_2'/>
<style name='Danger_3'/>
<style name='Warning'/>
<style name='Warning_2'/>
<style name='Warning_3'/>
<style name='Body'/>

I'm trying to process all styles whose name contains "Danger" or "Warning". Naive approach that doesn't work:

<xsl:template match="style[contains(@name, 'Danger|Warning')]">

I'm aware you can do this in XSLT 2.0 with exact matches:

"style[@name=('Danger','Warning')]"

Is there a solution for 'contains' matches?

This related question has an interesting solution: 'Use a pipe (or other appropriate character) delimited string', but despite the use of 'contains' that only works for exact matches (so it'll match 'Danger' but not 'Danger_1').

Martin Honnen · Accepted Answer · 2017-06-22 13:08:19Z

3

With XSLT/XPath 2.0 and later there is the matches function (http://maxtoroq.github.io/xpath-ref/fn/matches.html) with regular expression support style[matches(@name, 'Danger|Warning')].

Additionally you can also use style[some $s in ('Danger','Warning') satisfies contains(@name, $s)], that is also possible with XSLT/XPath 2.0 and later.

edited Jun 22, 2017 at 13:08

answered Jun 22, 2017 at 12:57

Martin Honnen

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Comments

Bernard Vander Beken · Accepted Answer · 2017-06-22 12:38:57Z

1

Have you tried the following?

<xsl:template match="style[contains(@name, 'Danger') or contains(@name, 'Warning')]">

answered Jun 22, 2017 at 12:38

Bernard Vander Beken

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1 Comment

Hobbes Over a year ago

I'd prefer a shorter solution if one exists (need to match 20 strings, not 2).

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