Selenium JavaScript to continue loop after exception

Question

for (let n = 0; n < someNumber; n++){ 
  try {
    driver.get(url[n]);
    driver.findElement(By.css("selector"));
  } catch (err){
    console.log(url[n] + "did not load");
  }
}

I am trying to loop through web pages in Javascript. I am looking for an element on the page. If I cannot find the element, I want it to log the URL and continue the loop. The problem is that my code just stops at the findElement and will stop execution. It never reaches my catch block. I just get the error below:

NoSuchElementError: no such element: Unable to locate element: {"method":"css selector"

What am I doing wrong?

Anuj Teotia · Accepted Answer · 2017-06-23 12:22:53Z

1

You are using wrong selector, If you want to locate the element using cssSelector then you should write something like this :

driver.findElement(By.cssSelector("Location of your WebElement"));
Example : 
driver.findElement(By.cssSelector("input[id=email]"));

In place of : driver.findElement(By.css("selector"));

findElement will throw an error if the element you're searching for doesn't exist. And if there is only one element you are looking for then you should write findElement or if there are many elements present then use findElements

edited Jun 23, 2017 at 12:22

answered Jun 23, 2017 at 5:47

Anuj Teotia

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1 Comment

qaNoob Over a year ago

This is in JavaScript, not Java. JavaScript Selenium locator for css correctly works the way i wrote it.

Monika · Accepted Answer · 2017-06-23 08:01:47Z

0

This error has come as you have used invalid locator. Your locator should be cssSelector not css.

Change this line driver.findElement(By.css("selector")) to driver.findElement(By.cssSelector("selector")) and your program would be working as expected.

answered Jun 23, 2017 at 8:01

Monika

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1 Comment

qaNoob Over a year ago

This is in JavaScript, not Java. This is the correct syntax in JavaScript for locating CSS.

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