How to test url string using regular expression

Question

Below is my code

/config\/info\/newplan/.test(string)

which will return true when find /config/info/newplan/ in string.

However, I would like to test different condition in the same time like below

/config\/info\/newplan/.test(string) || /config\/info\/oldplan/.test(string) || /config\/info\/specplan/.test(string)

which will return true if the string end up with either "newplan" or "oldplan" or "specplan"

My question is how to make a better code and not write "/config/\info/\xxxx\ so many times?

Wiktor Stribiżew · Accepted Answer · 2017-06-28 06:19:02Z

1

/config\/info\/(?:new|old|spec)plan/.test(string)
                ^^^^^^^^^^^^^^^

Pattern details:

config\/info\/ - a literal config/info/ substring
(?:new|old|spec) - a non-capturing group (where | separates alternatives) matching any one of the substrings: new, old or spec
plan - a literal plan substring

answered Jun 28, 2017 at 6:19

Wiktor Stribiżew

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Comments

axnet · Accepted Answer · 2017-06-28 06:30:07Z

1

this would be your bet

config\/info\/(newplan|oldplan|specplan)\/
OR
config\/info\/(newplan|oldplan|specplan)\/.test(string)

please see the example at [https://regex101.com/r/NyP1HP/1] as it doesn't allow other possibilities like following

/config/info/new1plan/
/config/info/newoldplan/
/config/info/specplan1/

answered Jun 28, 2017 at 6:30

axnet

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