j = True
while j == True:
area = raw_input("Elije la figura geometrica para calcular su area
\nCuadrado=1 \nTriangulo=2 \nCirculo=3\n")
if area == 1 :
acuadrado()
the problem is in the area.It is something in the syntax?
j = True
while j == True:
area = raw_input("Elije la figura geometrica para calcular su area
\nCuadrado=1 \nTriangulo=2 \nCirculo=3\n")
if area == 1 :
acuadrado()
the problem is in the area.It is something in the syntax?
raw_input in python2.x returns a "string" representation of the users input. Your wanting to do numerical comparison on the input, so you'll want to cast the area variable to an integer (int) before performing the comparison. Something like the following:
area = int(raw_input("Elije la figura geometrica..")
or
area = raw_input("Elije ...")
area = int(area)
then you can compare int values:
if area == 1 :
acuadrado()
etc...
altogether something like this might help you get along:
def acuadrado():
print 'acuadrado'
def atriangulo():
print 'atriangulo'
def acirculo():
print 'acirculo'
j = True
while j == True:
area = raw_input("Elije la figura geometrica para calcular su area \nCuadrado=1 \nTriangulo=2 \nCirculo=3\n")
area = int(area)
if area == 1 :
acuadrado()
elif area == 2:
atriangulo()
elif area == 3:
acirculo()
else:
print 'nada'
j = False
Also see How can I convert a string to an int in Python?
Hope that helps.