Handle multiple parameters in array_map call back

Question

I have the following code:

$a=array(15,12,13,25,27,36,18);
$b=array(1,1,1,1,1,1,1);//is it possible to pass only one value=1, instead of array containing seven 1's
// expectation: $b = array(1); or $b= 1; 
//instead of $b=array(1,1,1,1,1,1,1);

function array_add($p,$q){
   return($p+$q);
}
$c=array_map("array_add",$a,$b);

I want something like:

$a=array(15,12,13,25,27,36,18);
$b=array(1);

function array_add($p,$q){
   return($p+$q);
}
$c=array_map("array_add",$a,$b);

Any better solution thanks.

What are you trying to do? Please provide an example With expected behaviour. — msfoster
– msfoster, Commented Jul 4, 2017 at 7:20
$a=array(15,12,13,25,27,36,18); $b=array(1,1,1,1,1,1,1); // I want to use one value for all indexes instead of array i.e. $b = 1; function array_add($p,$q){ return($p+$q); } $c=array_map("array_add",$a,$b); — waqas
– waqas, Commented Jul 4, 2017 at 7:54

LF-DevJourney · Accepted Answer · 2017-07-04 07:25:55Z

1

You can use array_map as this, and pass the $param2 with use()

array_map(function($v) use($param2){
    //do something
}, $input);

answered Jul 4, 2017 at 7:25

LF-DevJourney

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Comments

msfoster · Accepted Answer · 2017-07-04 08:31:47Z

0

Have a look at array_walk

From Your example, it would be:

function array_add( &$item, $key, $toAdd) { 
   $item+=$toAdd;
}
array_walk($a, 'array_add', 1);

I would also recommend that you have a look at the answer provided using closure(use)

answered Jul 4, 2017 at 8:31

msfoster

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