While constructing the default constructor can not handle exception : type Exception thrown by implicit super constructor

Question

The code works fine until I try to make the code into a constructable class. When I attempt to construct an object from it I get the error

"Default constructor cannot handle exception type IOException thrown by implicit super constructor. Must define an explicit constructor"

This is when having to throw exceptions to FileReader and BufferedReader.

Thanks

EDIT:

FileReader textFilethree = new FileReader (xFile);
BufferedReader bufferedTextthree = new BufferedReader (textFilethree) ;
String lineThree = bufferedTextthree.readLine();

The xFile is gotten from the construction. Note that within this construction exceptions are thrown.

Jigar Joshi · Accepted Answer · 2011-07-21 08:05:15Z

6

Default constructor implicitly invokes super constructor which is assumed to be throwing some exception which you need to handle in sub class's constructor . for detailed answer post the code

class Base{

  public Base() throw SomeException{
    //some code
  }

}

class Child extends Base{
  public Child(){
   //here it implicitly invokes `Base()`, So handle it here
  }
}

edited Jul 21, 2011 at 8:05

answered Jul 21, 2011 at 7:35

Jigar Joshi

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7 Comments

Jigar Joshi Over a year ago

you need to add relevant construtor's

Ian Over a year ago

It just has the parameter for FileReader as a parameter of the constructor with exceptions thrown.

Jigar Joshi Over a year ago

so you need to catch or throw it in sub class's constructor

Ian Over a year ago

Yea I did throw it, but then I got the error message in my IDE when I tried to construct.

Jigar Joshi Over a year ago

again you need to handle it while constructing. it propogates

|

iammilind · Accepted Answer · 2011-07-21 07:43:41Z

3

Base class super.constructor is implicitly invoked by the extending class constructor:

class Base
{
  public Base () throws Exception
  {
    throw <>;
  }
}

class Derived extends Base
{
  public Derived ()
  {
  }
}

Now, one need to handle the exception inside Derived() or make the constructor as,

public Derived() throws Exception
{
}

Whatever method you new up the object of Derived, either you enclose it in try-catch or make that method throwing Exception as above. [Note: this is pseudo code]

answered Jul 21, 2011 at 7:43

iammilind

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1 Comment

Ian Over a year ago

I'm thinking of erring on forgetting about the ide error, I ran it and it was fine. Will I run into problems later if I do this?

Floating Sunfish · Accepted Answer · 2018-12-13 02:52:19Z

2

Just enclose your call to the Constructor in a Try-Catch.

answered Dec 13, 2018 at 2:52

Floating Sunfish

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Comments

Yusf · Accepted Answer · 2015-02-18 14:08:24Z

0

Any subclass which extends a super class whose default constructor handles some exception, a subclass must have a default constructor which implements the exception

class Super{ public Super() throws Exception {}}

class Sub extends Super{public Sub()throws Exception{//}}

answered Feb 18, 2015 at 14:08

Yusf

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Comments

Dharman · Accepted Answer · 2021-03-05 04:08:17Z

0

if you have something like this

class example{
    public void fileReader(String path) throws Exception{
         //some code that throws Exception
    }
 }

Make sure to use that same sintaxis on the method you are trying to make the object

class implementation{
     public void someMethod() throws Exception{
          example object = new example();
          example.filereader("C:\\....");
      }
  }

happened to me while using apache poi

edited Mar 5, 2021 at 4:08

Dharman♦

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answered Mar 5, 2021 at 4:02

Jesus Hernandez

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