My understanding is that bellow code will create an array name digits which contains all digits from n, I'm I right?
var n = 123456789; var digits = (""+n).split("");
But I did'n understood (""+n) ? Can anyone help me? Thanks in advance.
5 Answers
n is type of a number, with (""+n), you are basically converting n to a string, so you can use split method. numbers do not have a split method
Comments
It is doing the job of implicit type casting from int to string. For ex.
4 + 2
returns 6
4 + 2 + "2"
returns 62
"2" + 2 + 4
returns 224
The integers following "" are implicitly converted to string and cancatenated.
Comments
var n = 123456789; create a variable n of numeric type. When you use +"" with a variable of numeric type javascript autamatically treat it as string and the operation return a string. So (""+n) will cast the n variable to string type.
Comments
When concat a number with string, js cast it to string. In your code, n is number, but when concat with a empty string(""), casting to string. In other way you can call toString() function. You can run follow snippet to try it
var n = 123456789;
console.log(typeof n); //number
console.log(typeof (""+n)); //string
console.log((""+n).split(""));
console.log(n.toString().split(""));
1 Comment
Ameet
Thank you Mohammad for the detail explanation.
(""+n) means type casting the variable n into string
var n = 32; // n is integer type
n = "" + n; // now n is string type (n = "32")
var digits = n.split("");//execute string split function
//now digits = ['3','2'] (array of chars or single string charector)
