Manipulate file path for output using split

Question

I have a file path

e:\pst\Section\RMS\user\\

final output needs to be Section/user

Currently using

$result.filepath = $pst.FilePath.Split('\')[2..4] -join '/'

but that gives me

Section/RMR/User

How can I manipulate the split to only pull 2 and 4 to equal Section/User?

Maximilian Burszley · Accepted Answer · 2017-07-19 17:40:23Z

3

You have an error in your example:

$pst = 'e:\pst\Section\RMS\user\'
$result.filepath = $pst.FilePath.Split('\')[2..4] -join '/'
$result.filepath
Section/RMS/user

Should be:

$pst = 'e:\pst\Section\RMS\user\'
$result.filepath = $pst.FilePath.Split('\')[2,4] -join '/'
$result.filepath
Section/user

Note the comma instead of the range operation.

answered Jul 19, 2017 at 17:40

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1 Comment

Thanks.I got it to work using $result.filepath = $pst.FilePath.Split('\')[2,4] -join '/ -replace('RMS/') but i like your solution better