Python, find a specific character in a string in a list

Question

If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(items)

you want all items not starting with a or all items after the first starting with a? — bogdanciobanu
– bogdanciobanu, Commented Jul 20, 2017 at 20:50
Agree with @MosesKoledoye but you should post what the specific error is (which you did not do) and what is expected (which you did). — AGN Gazer
– AGN Gazer, Commented Jul 20, 2017 at 20:51
@bogdanciobanu He wants all items that DO NOT start with 'a' — AGN Gazer
– AGN Gazer, Commented Jul 20, 2017 at 20:52

cs95 · Accepted Answer · 2017-07-20 21:01:22Z

1

How about a filter?

In [191]: print('\n'.join(filter(lambda x: x[0] != 'a', ["abc", "xyz", "test"])))
xyz
test

edited Jul 20, 2017 at 21:01

answered Jul 20, 2017 at 20:58

cs95

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2 Comments

AGN Gazer Over a year ago

Does he want a list or he simply wants to print items (i.e., one per line)?

cs95 Over a year ago

@AGNGazer The question is open to interpretation :) Probably the latter, but that's just an extension of this.

AGN Gazer · Accepted Answer · 2017-07-20 20:57:18Z

0

def loopy(items):
    for item in items:
        if not item.startswith('a'):
            print(item)

answered Jul 20, 2017 at 20:57

AGN Gazer

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Comments

Dadep · Accepted Answer · 2017-07-20 21:09:34Z

0

with few correction :

>>> l=['abi', 'crei', 'fci', 'anfe']
>>> def loopy(list):
...     for i in list:
...             if i[0]=='a':
...                     continue
...             else:
...                     print i
... 
>>> loopy(l)
crei
fci

that you can make shorter this way :

>>> def loopy(list):
...     for i in list: 
...             if i[0]!='a':
...                     print i
... 
>>> loopy(l)
crei
fci

or to print in one line :

>>> def loopy3(list):
...     for i in list:
...             print i if i[0]!='a' else '',
... 
>>> loopy3(l)
 crei fci

but you can also use a list comprehension as suggest by bogdanciobanu :

>>> def loopy2(list):
...     print [i for i in list if i[0]!='a']
>>> loopy2(l)
['crei', 'fci']

edited Jul 20, 2017 at 21:09

answered Jul 20, 2017 at 20:54

Dadep

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