Comparing array values with mysqli result

Question

Can someone help me to solve this issue?

Below code i used in an edit page, and i want to compare the checkbox values and if it is matching make it as checked.

Example of my two array values

$CategoryDetails : Array ( [0] => 6 [1] => 1 )
$Category_data : Array ( [0] => 1 [1] => 3 [2] => 6 [3] => 2 [4] => 4 [5] => 7)

$Category_data is am using to create checkbox and $CategoryDetails is the selected values. So as per above eg checkbox 1 & 3 should be checked, but below code giving me only one checked ie. checkbox3

I need to compare each value of array1 with array2.

<?php
    $CategoryDetails = isset($category_list) ? $category_list : ' ';
    $Category = dbSelectByWhere("Highlight_categories", "WHERE Highlight_cat_status=1", "Order By Highlight_Category_name");
    $k = 0;
    while ($Category_data = dbFetchArray($Category)) {
        ?>
        <input type="checkbox" name="category[]" id="Category" value="<?php echo $Category_data['Highlight_category_id']; ?>" data-parsley-mincheck="1" required class="flat" <?php
        if (isset($CategoryDetails) && ($CategoryDetails[$k] == $Category_data['Highlight_category_id'])) {
            echo 'checked';
            if ($k < (count($CategoryDetails) - 1)) {
                $k++;
            }
        }
        ?>/> <?php echo $Category_data['Highlight_Category_name']; ?>
    <?php } ?>

JYoThI · Accepted Answer · 2017-08-16 04:46:19Z

2

1st : You need to use in_array function.

2nd : in_array function searches an array for a specific value .if value exists it will return true else it will return false .

3rd : If empty declare the variable as array

$CategoryDetails = isset($category_list) ? $category_list : array();

PHP :

while ($Category_data = dbFetchArray($Category)) {
        ?>
        <input type="checkbox" name="category[]" id="Category" value="<?php echo $Category_data['Highlight_category_id']; ?>" data-parsley-mincheck="1" required class="flat" <?php
        if (isset($CategoryDetails) && in_array($Category_data['Highlight_category_id'],$CategoryDetails)) {
            echo 'checked';
        }
        ?>/> <?php echo $Category_data['Highlight_Category_name']; ?>
        <?php } ?>

edited Aug 16, 2017 at 4:46

answered Aug 16, 2017 at 4:35

JYoThI

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1 Comment

Amit Joshi Over a year ago

Think it should be $CategoryDetails = isset($category_list) ? $category_list : array();

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