type conversion to integer in ruby

Question

I am using latest ruby version[ruby 2.4.1p111]

I am getting the result of '123'.to_i +12 to 171

irb(main):021:0> '123'.to_i + 12
=> 135
irb(main):022:0> '123'.to_i +12
=> 171
irb(main):023:0> 123 + 12
=> 135
irb(main):024:0> 123 +12
=> 135

Can you help me understand the second operation here.

Simple Lime · Accepted Answer · 2017-08-20 08:39:57Z

3

You ended up calling the unary plus operator in the second example, which

Returns the receiver’s value

and then you ended up with (essentially):

'123'.to_i 12

and since, to_i takes an argument, base, you ended up converting '123' to an integer in base 12, which is, apparently, 171.

answered Aug 20, 2017 at 8:39

Simple Lime

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Comments

Ursus · Accepted Answer · 2017-08-20 08:38:48Z

2

to_i can take an argument, the base, and its default is 10.

What you did is:

'123'.to_i(12)

answered Aug 20, 2017 at 8:38

Ursus

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