I have a NSMutableArray and want to add a 2 dimensional NSArray with integer parameters to it each time. But after use that values their IDs not show as Integers.And I tried @[i,j] too but it didn't work. Here is my code :
resault = [[NSMutableArray alloc]initWithCapacity:40];
for (int i=0; i<5; i++)
{
for (int j=0; j<5; j++)
{
[resault addObject:@[@(i),@(j)]];
}
}
Use this code -
NSMutableArray*resault = [[NSMutableArray alloc]initWithCapacity:40];
for (int i=0; i<5; i++)
{
NSMutableArray*array = [[NSMutableArray alloc]initWithCapacity:40];
for (int j=0; j<5; j++)
{
[array addObject:@[@(i),@(j)]];
}
[resault addObject:array];
}
You can try this:
NSMutableArray * ma = [NSMutableArray new];
for (int i = 0; i < 10; i++){
for (int d = 0; d < 10; d++){
[ma addObject:[NSString stringWithFormat:@"%i%i",i,d]];
}
}
NSLog(@"id is %@", ma);
Cycle through the I loop, then the D loop and add into the array as NSString objects. If you need them as NSNumbers, just convert them later. If you are counting up from 0 to n, you can use a single for loop (e.g. from 0 to 100 would work in the example above), while nesting for loops works better if you're using non numerical IDs.
If you want to keep the 0 character in front of IDs below ten, using a single for loop:
NSMutableArray * ma = [NSMutableArray new];
for (int i = 0; i < 100; i++){
[ma addObject:[NSString stringWithFormat:@"%02d",i]];
}
NSLog(@"id is %@", ma);
Using your method:
NSMutableArray * ma = [NSMutableArray new];
for (int i = 0; i < 10; i++){
for (int d = 0; d < 10; d++){
[ma addObject:@[@(i),@(d)]];
}
}
int thirtiethI = [ma[30][0] intValue];
int thirtiethD = [ma[30][1] intValue];
NSLog(@"thirtieth: %i %i", thirtiethI, thirtiethD);
resault = [[NSMutableArray alloc]initWithCapacity:40];
for (int i=0; i<5; i++)
{
for (int j=0; j<5; j++)
{
[resault addObject:[NSArray arrayWithObjects:
[NSNumber numberwithInt:i],
[NSNumber numberWithInt:j],
nil]
];
}
}
You can then access the i,j pairs by running through the result array and extracting the stored NSArray and getting the first and second objects sorted therein.
First of all you have to understand the int, float these basic types can not be deposited into the array
So when you add it @(i), this means [NSNumber numberWithInt: i]
The array is the type of NSNumber
If you want to take it out
int result = [resault [30] [0] intValue];
