Searching keywords from one array against values of another array - php

Question

I have 2 arrays. One with bad keywords and the other with names of sites.

$bad_keywords = array('google', 
                      'twitter', 
                      'facebook');

$sites = array('youtube.com', 'google.com', 'm.google.co.uk', 'walmart.com', 'thezoo.com', 'etc.com');

Simple task: I need to filter through the $sites array and filter out any value that contains any keyword that is found in the $bad_keywords array. At the end of it I need an array with clean values that I would not find any bad_keywords occurring at all.

I have scoured the web and can't seem to find a simple easy solution for this. Here are several methods that I have tried:
1. using 2 foreach loops (feels slower - I think using in-built php functions will speed it up)
2. array_walk
3. array_filter

But I haven't managed to nail down the best, most efficient way. I want to have a tool that will filter through a list of 20k+ sites against a list of keywords that may be up to 1k long, so performance is paramount. Also, what would be the better method for the actual search in this case - regex or strpos?

What other options are there to do this and what would be the best way?

@ArunKumaresh Output: the filtered $sites array (i.e. does not contain any elements that a bad_keyword is found inside it's value) — Ben
– Ben, Commented Aug 23, 2017 at 12:03

RomanPerekhrest · Accepted Answer · 2017-08-23 12:04:32Z

2

Short solution using preg_grep function:

$result = preg_grep('/'. implode('|', $bad_keywords) .'/', $sites, 1);
print_r($result);

The output:

Array
(
    [0] => youtube.com
    [3] => walmart.com
    [4] => thezoo.com
    [5] => etc.com
)

answered Aug 23, 2017 at 12:04

RomanPerekhrest

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