4

I asked this question awhile ago, but didn't get a usuable answer. Basically, I can't get my method for duplicating objects to work due to invalid cast exceptions. But I can cast things fine outside of the duplication method.

Here's the duplication method

public static class ObjectDuplicator
{
    public static T Clone<T>(T source)
    {
        if (!typeof(T).IsSerializable)
        {
            throw new ArgumentException("the Type must be serializable.", "source");
        }

        if (Object.ReferenceEquals(source, null)) //dont try to serialize a null object
        {
            return default(T);
        }

        IFormatter formatter = new BinaryFormatter();
        Stream stream = new MemoryStream();
        using (stream)
        {
            formatter.Serialize(stream, source);
            stream.Seek(0, SeekOrigin.Begin);
            return (T)formatter.Deserialize(stream);
        }
    }
}

The problem is this: when I call this method using the code below

public void AddJob(Job job)
{
    if (!Jobs.Contains(job))
    {
        Job newcopy = Utilities.ObjectDuplicator.Clone<Job>(job);

        Jobs.Add(newcopy);
    }
}

it throws this exception:

System.InvalidCastException was unhandled Message=Unable to cast object of type 'KH.CharacterClasses.Freelancer' to type 'KH.CharacterClasses.Job'

Now, the type of job I'm adding is an inherited class from Job, (Freelancer) and the code for those two classes is below

[Serializable]
public class Job : Ability
{
    protected JobCommand basecommand1;
    protected JobCommand basecommand2;
    protected JobCommand basecommand3;
    protected JobCommand basecommand4;
    protected JobCommand command1;
    protected JobCommand command2;
    protected JobCommand command3;
    protected JobCommand command4;
    bool mastered;
    protected FFJob job;
    protected string name;
    int level;

    public FFJob SetJob
    {
        get
        {
            return job;
        }
    }

    public bool Mastered
    {
        get
        {
            return mastered;
        }
    }

    public JobCommand Command1
    {
        get
        {
            return command1;
        }
        set
        {
            command1 = value;
        }
    }

    public JobCommand DefaultCommand1
    {
        get
        {
            return basecommand1;
        }
    }

    public JobCommand Command2
    {
        get
        {
            return command2;
        }
        set
        {
            command2 = value;
        }
    }

    public JobCommand DefaultCommand2
    {
        get
        {
            return basecommand2;
        }
    }

    public JobCommand Command3
    {
        get
        {
            return command3;
        }
        set
        {
            command3 = value;
        }
    }

    public JobCommand DefaultCommand3
    {
        get
        {
            return basecommand3;
        }
    }

    public JobCommand Command4
    {
        get
        {
            return command4;
        }
        set
        {
            command4 = value;
        }
    }

    public JobCommand DefaultCommand4
    {
        get
        {
            return basecommand4;
        }
    }

    public Job(string name, string description, int jobID)
        : base(name, description, jobID, -1, -1, null, null, -1, -1)
    {
    }

    public static bool operator ==(Job job1, Job job2)
    {
        if (System.Object.ReferenceEquals(job1, job2))
            return true;
        if (((object)job1 == null) || ((object)job2 == null))
            return false;
        return (job1.Name == job2.Name && job1.UID == job2.UID);
    }

    public static bool operator !=(Job job1, Job job2)
    {
        return !(job1 == job2);
    }


    // public abstract void CharacterModifier(BaseCharacter character);

    // public abstract void CharacterDemodifier(BaseCharacter character);
}

[Serializable]
public class Freelancer : Job
{
    public Freelancer()
        : base("Freelancer", "A character not specializing in any class. Can combine the power of all mastered Jobs.", Globals.JobID.ID)
    {
        basecommand1 = JobCommand.Attack;
        basecommand2 = JobCommand.Free;
        basecommand3 = JobCommand.Free;
        basecommand4 = JobCommand.Items;
        command1 = basecommand1;
        command2 = basecommand2;
        command3 = basecommand3;
        command4 = basecommand4;
        job = FFJob.Freelancer;
    }
}

I really don't know what the issue is. As I said, casting works fine outside of this method, and I know this code has worked before. Any ideas?

Thanks

3
  • The serialization code looks okay. I'm pretty sure I do this exact thing somewhere. I'll take a look. Commented Jan 4, 2011 at 5:37
  • Yep I serialize a derived type and on deserialization cast it to it's base type fine. Your problem looks very wierd, I don't understand it. Sorry I can't help. Commented Jan 4, 2011 at 5:50
  • Can you provide an entire exception stacktrace? Also inner exception. Lastly, try moving the cast to T to another line, so you can inspect the object. Commented Jan 4, 2011 at 6:11

2 Answers 2

1

I figured it out. At some point, I compiled it as a .dll to reference in another project. I forgot to delete the .dll from the bin directory, so the program was loading my classes from the dll, not from the new version of the code. I realized that after I tried to do a straight duplication of the same type of objct and saw it was referecing something from the .dll and from the .exe. Deleting the .dll fixed it. Silly me.

Sign up to request clarification or add additional context in comments.

Comments

0

I you just want duplication, instead of serialization, why not just implement IClonable? Every type has a protected method called MemberwiseClone that eases the working involved considerably.

1 Comment

Well I just think it's easier to have one method for duplicating objects then a method for each type

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.