Unix command "sed" to replace PHP associative array values

Question

I am trying to use the Linux sed command to replace associative array values in a PHP config file. On macOS everything goes ok, but on linux I am getting an error.

Command

sed -i .back "s/'param'.*=>.*/'param' => 'value',/" config.php

Error (linux): sed: -e expression #1, char 1: unknown command: `.'

What proper solution would there be to replace PHP array values with the sed command?

show a fragment of your config file with associative array values to replace — RomanPerekhrest
– RomanPerekhrest, Commented Sep 4, 2017 at 7:57

hek2mgl · Accepted Answer · 2017-09-04 07:50:23Z

2

There must be no space between -i and .back on GNU sed:

sed -i.back 's/.../.../' file

If you don't care about the backup file you can omit the option value completely on GNU sed:

sed -i 's/.../.../' file

answered Sep 4, 2017 at 7:50

hek2mgl

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