String in C programming

Question

Hi I have a question about subsequent code in C:

 #include <stdio.h>
 #include <stdlib.h>

int main()
{
    char name[10];
    printf("Enter your name: \n");
    scanf_s("%s", &name);

    printf("Your name is: %s", name);


    return 0;
}

It works perfectly using CodeBlocks, but using Microsoft Visual Studio 2015 it just doesn't work. This warning is always shown:

Warning C4473   'scanf_s' : not enough arguments passed for format string

Could you please give me a hint on what's going on?

NOTE: In Visual Studio I always use scanf_s instead of scanf.

scanf_s() is not a standard function and requires extra parameters. Read the documentation. — Iharob Al Asimi
– Iharob Al Asimi, Commented Sep 9, 2017 at 13:59
"In Visual Studio I always use scanf_s instead of scanf." Why? — alk
– alk, Commented Sep 9, 2017 at 14:03
I'm still confused as to why it would work on command line instead of VS. If I understand correctly, you change the function when you go from one to the other? In that case, I have the same questions as @alk — information_interchange
– information_interchange, Commented Sep 9, 2017 at 14:06
@alk because vs2015 will refuse to compile the code. @PinkP use #define _CRT_SECURE_NO_WARNINGS before #include <stdio.h> and other 'include' files to disable deprecation and use scanf() normally. — machine_1
– machine_1, Commented Sep 9, 2017 at 14:11

Debabrata · Accepted Answer · 2017-09-09 14:01:52Z

1

"scanf_s" needs an extra parameter that is buffer size.

for example:

scanf_s("%s", name, 1024);

answered Sep 9, 2017 at 14:01

Debabrata

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