Preg_replace in following string

Question

I want to replace content from below string,

I want to replace line The part has been repaired to upto end p tag.

$text = "<p>701082 Range Control Board from Dacor is a manufacturer approved part. The part has been repaired to Dacor's specifications resulting in the highest performance with superior quality</p>";

preg_replace('/The part has been repaired to.*?<\/p>/U', '</p>', $text);

print_r($text);

I tried above preg_replace function but its not working as expected.

So you want to replace everything to the end of the string with a </p>. so your string becomes <p>701082 Range Control Board from Dacor is a manufacturer approved part.</p> — Norris Oduro
– Norris Oduro, Commented Sep 12, 2017 at 6:32
make sure you consider @Andreas answer If you need something other than regex. And dont forget to mark my answer if it is helpful — Norris Oduro
– Norris Oduro, Commented Sep 12, 2017 at 6:43

Norris Oduro · Accepted Answer · 2017-09-12 06:35:13Z

1

The preg_replace function returns the value of the string after the pattern has been applied to it. Assign a the result to a variable and print_r the variable.

$text = "<p>701082 Range Control Board from Dacor is a manufacturer approved part. The part has been repaired to Dacor's specifications resulting in the highest performance with superior quality</p>";

$result  = preg_replace('/The part has been repaired to.*?<\/p>/U', '</p>', $text);

print_r($result);

answered Sep 12, 2017 at 6:35

Norris Oduro

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Andreas · Accepted Answer · 2017-09-12 06:37:45Z

0

You can use strpos to find the position of your "end" and use substr to substring it.

$text = "<p>701082 Range Control Board from Dacor is a manufacturer approved part. The part has been repaired to Dacor's specifications resulting in the highest performance with superior quality</p>";

Echo substr($text, 0, strpos($text, "The part has been repaired to")). "</p>";

https://3v4l.org/tR5tt

answered Sep 12, 2017 at 6:37

Andreas

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