Order second level array values based on a keyword [closed]

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I'm trying to sort the second-level values based on a specific keyword. In this case that keyword is red.

If I inspect the steps in the callback function it seems to work, but the final result is unchanged. It also sorts the top-level keys alphabetically.

$data = array(
    'foo' => array(
        'red', 'green'
    ),
    'bar' => array(
        'yellow', 'red'
    ),
);

print_r($data);

uasort($data, function($data) {
    $matches = preg_grep("/red/", $data);

    $rest = array_diff($data, $matches);

    $order = array_merge($matches, $rest);

    return $order;

});

print_r($data);

What is the desired result? Do we have enough sample data to verify correct answers? — mickmackusa
– mickmackusa ♦, Commented Feb 2 at 14:40

Calimero · Accepted Answer · 2017-09-15 00:08:45Z

2

Your code doesn't work as intended because uasort() only sorts the array you pass to it in the first argument, the first level array ($data). The rest of your code, although running and syntactically correct, does not help either.

Here is a working example :

$data = array(
    'foo' => array(
        'red', 'green'
    ),
    'bar' => array(
        'yellow', 'red'
    ),
);

array_walk($data,function(&$v){
    uasort($v,function($a,$b){
        return preg_match('/red/',$a)?-1:1;
});});

print_r($data);

array_walks() iterates through the first-level array.
uasort() is provided in the callback, and handles the sorting part of the second-level arrays.
preg_match() is then used to match the string and return a value suitable for reordering in the callback to uasort().

answered Sep 15, 2017 at 0:08

Calimero

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1 Comment

mickmackusa Feb 2 at 14:38

function($a,$b){ return preg_match('/red/',$a)?-1:1; } makes NO sense -- there is no $b evaluation.

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