This works, but I don't understand why:
function hasUppercase(input) {
for (var i = 0; i < input.length; i++) {
if (input[i] === input[i].toUpperCase()) {
return true
} else {
return false
}
}
}
console.log(hasUppercase("no"));
console.log(hasUppercase("Yes"));How come the 'true' for the 'Yes' beats all the falses?
For all characters, you could just return (early exit) if you have found one uppercase letter - in cases of lower case, you need to iterate to the end of the string.
function hasUppercase(input) {
for (var i = 0; i < input.length; i++) {
if (input[i] === input[i].toUpperCase()) {
return true;
}
}
return false;
}
console.log(hasUppercase("no"));
console.log(hasUppercase("Yes"));
console.log(hasUppercase("yeS"));
Your problems are due to the return false statement, which makes function return on first non-uppercase character. The way it is constructed, it will always return after first character. Others already gave you solutions, I'll give you more concise way to achieve the same:
const hasUpperCase = in => in.split('').some(c => c === c.toUpperCase());
// Demo:
console.log(hasUpperCase('no'));
console.log(hasUpperCase('yeS'));function hasUpperCase(input) {
return input.split('').some(function isCharUpperCase(char) {
return char === char.toUpperCase();
});
}
// Demo:
console.log(hasUpperCase('no'));
console.log(hasUpperCase('yeS'));This function checks only the first character of a given input. If the first character is in Uppercase then it returns true else it returns false. The function quits after first iteration.
So if the given input is like 'yEs' then it returns false. As it checks only the first character 'y' and exits.
returnstatement exits the function immediately.hasUppercase("ayyLmao")returns false.input[0]) you're testing for matches the case but take it off and you'll see for yourself