I have a python string like this;
input_str = "2548,0.8987,0.8987,0.1548"
I want to remove the sub-string at the end after the last comma, including the comma itself.
The output string should look like this;
output_str = "2548,0.8987,0.8987"
I am using python v3.6
split and join','.join(input_str.split(',')[:-1])
# Split string by the commas
>>> input_str.split(',')
['2548', '0.8987', '0.8987', '0.1548']
# Take all but last part
>>> input_str.split(',')[:-1]
['2548', '0.8987', '0.8987']
# Join the parts with commas
>>> ','.join(input_str.split(',')[:-1])
'2548,0.8987,0.8987'
rsplitinput_str.rsplit(',', maxsplit=1)[0]
rere.sub(r',[^,]*$', '', input_str)
If you are gonna to use it multiple times make sure to compile the regex:
LAST_ELEMENT_REGEX = re.compile(r',[^,]*$')
LAST_ELEMENT_REGEX.sub('', input_str)
rsplit is the cleanest in my opinion.
.rpartition - it's optimised for a split case of 0 or 1...You can try this simplest one. Here we are using split, pop and join to achieve desired result.
input_str = "2548,0.8987,0.8987,0.1548"
list= input_str.split(",") #Split string over ,
list.pop() #pop last element
print(",".join(list)) #joining list again over ,
Assuming that there is definitely a comma in your string:
output_str = input_str[:input_str.rindex(',')]
That is "Take everything from the start of the string up to the last index of a comma".
There's the split function for python :
print input_str.split(',')
Will return :
['2548,0.8987,0.8987', '0.1548']
But in case you have multiple commas, rsplit is here for that :
str = '123,456,789'
print str.rsplit(',', 1)
Will return :
['123,456','789']
split(',') will split on every comma, not just the last one.
Here you go
sep = ','
count = input_str.count(sep)
int i=0;
output = ''
while(i<count):
output += input_str.split(sep, 1)[i]
i++
input_str = output
