I have a string like:
const stringVar = ":20:9077f1722efa3632 :12:700 :77E: :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE"
I want to create JSON from above stringVar:
{
":21:" : "9077f1722efa3632",
":12:" : "700",
":27A:": "2/2",
":21A:": "9077f1722efa3632",
":27:" : "1/2",
":40A:": "IRREVOCABLE"
}
So, I was thinking I could split with regular expression (":(any Of char/digit):")
I would make the first part the key and the second part its value.
The regular expression /(:\w+:)(\S+)/ matches the whole key:value pair. You can add the g modifier, and then use it in a loop to get all the matches and put them into the object.
const stringVar = ":20:9077f1722efa3632 :12:700 :77E: :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE"
var regexp = /(:\w+:)(\S+)/g;
var obj = {};
var match;
while (match = regexp.exec(stringVar)) {
obj[match[1]] = match[2];
}
console.log(obj);If you want to create an array of {key: ":20:", value: "9077f1722efa3632"}, you can modify the code to:
const stringVar = ":20:9077f1722efa3632 :12:700 :77E: :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE"
var regexp = /(:\w+:)(\S+)/g;
var array = [];
var match;
while (match = regexp.exec(stringVar)) {
array.push({key: match[1], value: match[2]});
}
console.log(array);If the values can contain space, change the regexp to:
/(:\w+:)([^:]+)\s/g
This will match anything not containing : as the value, but not include the last space.
:key:value pair.You can achieve the same result without using regex.
const stringVar = ":20:9077f1722efa3632 :12:700 :77E:xxx :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE";
const result = stringVar
.split(' ')
.reduce((ret, current) => {
const pos = current.indexOf(':', 1);
ret[current.substring(0, pos + 1)] = current.substring(pos + 1);
return ret;
}, {});
console.log(result);