Better way to ask user input in integer form in Python?

Question

So I'm kind of very beginner to programming and just learning yet the basics. Now I would like to have my python program to ask the user to give a number and keep asking with a loop if string or something else is given instead.

So this is the best I came out with:

value = False
while value == False:
    a = input("Give a number: ")
    b = 0
    c = b
    try:
        int(a)
    except ValueError:
        print("No way")
        b += 1
    if c == b:
        value = True

So is there easier and better way to do this?

Yes there is a better way, but if you are as much of a beginner as you say you are, good job on thinking it through and doing something that made sense in your head to get it to work — RSon1234
– RSon1234, Commented Oct 5, 2017 at 5:33

amarynets · Accepted Answer · 2017-10-05 05:46:55Z

3

You can use this:

while True:
    try:
        a = int(input("Give a number: "))
        break
    except ValueError:
        print("No way")

or this:

while True:
    a = input("Give a number: ")
    if a.isdigit():
        break
    print("No way")

edited Oct 5, 2017 at 5:46

answered Oct 5, 2017 at 5:32

amarynets

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3 Comments

PRMoureu Over a year ago

i think OP asks for keeping the loop running if the answer is not valid

amarynets Over a year ago

@PRMoureu, yes, my mistake. But it has no sense

PRMoureu Over a year ago

it's just to make the user input a valid number

vidstige · Accepted Answer · 2017-10-05 13:27:13Z

1

while True:
    try:
        a = int(input("Give a number: "))
        break
    except ValueError:
        print("No way")
        continue

This will continue to prompt the user for an integer till they give one.

edited Oct 5, 2017 at 13:27

vidstige

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answered Oct 5, 2017 at 5:41

Jacob John

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3 Comments

PRMoureu Over a year ago

(the last continue is not needed if there is no code after)

Jacob John Over a year ago

The continue makes it loop, not continue to the end

Jacob John Over a year ago

Otherwise it would keep going once they gave an integer

Sudeep Padalkar · Accepted Answer · 2017-10-05 05:41:56Z

0

value = True
while value == True:
     a = input("Give a number: ")
     try:
        int(a)
     except ValueError:
        print("No way")
        continue
     print("Yay a Number:", a)
     value = False

Is this what you need?

answered Oct 5, 2017 at 5:41

Sudeep Padalkar

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