Make part of a regex match in python optional [duplicate]

Question

I'm trying to match a URL using re but am having trouble in regards to making part of the match optional.

import re

x = raw_input('Link: ')
reg = '(http|https)://(iski|www\.iskis|iskis)\.(in|com)/[A-Za-z0-9?&=/?_]+'
if re.match(reg, x):
    print 'True'

Currently, the above code would match something like:

https://iskis.com/?loc=shop_view_item&item=220503032

I would like to alter the regular expression to make the following, [A-Za-z0-9?&=/?_]+ an option - As such, anything after the slash isn't required, so the following should match:

https://iskis.com

I'm sure there is a simple solution but I don't know how to go about solving this.

mypetlion · Accepted Answer · 2017-10-05 23:43:52Z

1

reg = '(http|https)://(iski|www\.iskis|iskis)\.(in|com)(/[A-Za-z0-9?&=/?_]+)?$'

Should do it. Surround the character class with () so it's a group, put a ? after it to make the text match 0-1 instances of that group, and put a $ at the end so that the regex will match to the end.

EDIT:

Come to think of it, you could use the optional match elsewhere in your regex.

reg = '(https?)://(www\.)?(iskis?)\.(in|com)(/[A-Za-z0-9?&=/?_]+)?$'

answered Oct 5, 2017 at 23:43

mypetlion

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