how to remove json object key and value.?

Question

I have a json object as shown below. where i want to delete the "otherIndustry" entry and its value by using below code which doesn't worked.

var updatedjsonobj = delete myjsonobj['otherIndustry'];

How to remove Json object specific key and its value. Below is my example json object where i want to remove "otherIndustry" key and its value.

var myjsonobj =  {
      "employeeid": "160915848",
      "firstName": "tet",
      "lastName": "test",
      "email": "[email protected]",
      "country": "Brasil",
      "currentIndustry": "aaaaaaaaaaaaa",
      "otherIndustry": "aaaaaaaaaaaaa",
      "currentOrganization": "test",
      "salary": "1234567"
    };
delete myjsonobj ['otherIndustry'];
console.log(myjsonobj);

where the log still prints the same object without removing 'otherIndustry' entry from the object.

Possible duplicate of Remove key-value pair from JSON object — Pankaj Makwana
– Pankaj Makwana, Commented Oct 6, 2017 at 6:27
Your code should work, can you create a MVCE stackoverflow.com/help/mcve — gurvinder372
– gurvinder372, Commented Oct 6, 2017 at 6:28
which doesn't worked What was the result? can you please explain? — Rajesh Dixit
– Rajesh Dixit, Commented Oct 6, 2017 at 6:31
Nope @Alexandru-IonutMihai, actually my code is var myjsonobj ={ "employeeid": "160915848", "firstName": "tet", "lastName": "test", "email": "[email protected]", "country": "Brasil", "currentIndustry": "aaaaaaaaaaaaa", "otherIndustry": "aaaaaaaaaaaaa", "currentOrganization": "test", "salary": "1234567" }; delete myjsonobj ['otherIndustry']; console.log(myjsonobj ); still prints the same object. :( — krish kr
– krish kr, Commented Oct 6, 2017 at 7:03

Vince · Accepted Answer · 2020-11-17 11:04:20Z

128

delete operator is used to remove an object property.

delete operator does not returns the new object, only returns a boolean: true or false.

In the other hand, after interpreter executes var updatedjsonobj = delete myjsonobj['otherIndustry']; , updatedjsonobj variable will store a boolean value.

How to remove Json object specific key and its value ?

You just need to know the property name in order to delete it from the object's properties.

delete myjsonobj['otherIndustry'];

let myjsonobj = {
  "employeeid": "160915848",
  "firstName": "tet",
  "lastName": "test",
  "email": "[email protected]",
  "country": "Brasil",
  "currentIndustry": "aaaaaaaaaaaaa",
  "otherIndustry": "aaaaaaaaaaaaa",
  "currentOrganization": "test",
  "salary": "1234567"
}
delete myjsonobj['otherIndustry'];
console.log(myjsonobj);

If you want to remove a key when you know the value you can use Object.keys function which returns an array of a given object's own enumerable properties.

let value="test";
let myjsonobj = {
      "employeeid": "160915848",
      "firstName": "tet",
      "lastName": "test",
      "email": "[email protected]",
      "country": "Brasil",
      "currentIndustry": "aaaaaaaaaaaaa",
      "otherIndustry": "aaaaaaaaaaaaa",
      "currentOrganization": "test",
      "salary": "1234567"
}
Object.keys(myjsonobj).forEach(function(key){
  if (myjsonobj[key] === value) {
    delete myjsonobj[key];
  }
});
console.log(myjsonobj);

edited Nov 17, 2020 at 11:04

Vince

5445 silver badges15 bronze badges

answered Oct 6, 2017 at 6:28

Mihai Alexandru-Ionut

48.6k14 gold badges106 silver badges132 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Rajesh Dixit Over a year ago

So irrespective of return value, will the key:value be deleted from object, as per OP's code?

Ollie Over a year ago

you can also use dot notation: delete myjsonobj.otherIndustry;

Mohammed Amir Ansari · Accepted Answer · 2019-08-26 16:15:40Z

There are several ways to do this, lets see them one by one:

delete method: The most common way

const myObject = {
    "employeeid": "160915848",
    "firstName": "tet",
    "lastName": "test",
    "email": "[email protected]",
    "country": "Brasil",
    "currentIndustry": "aaaaaaaaaaaaa",
    "otherIndustry": "aaaaaaaaaaaaa",
    "currentOrganization": "test",
    "salary": "1234567"
};

delete myObject['currentIndustry'];
// OR delete myObject.currentIndustry;
  
console.log(myObject);

By making key value undefined: Alternate & a faster way:

let myObject = {
    "employeeid": "160915848",
    "firstName": "tet",
    "lastName": "test",
    "email": "[email protected]",
    "country": "Brasil",
    "currentIndustry": "aaaaaaaaaaaaa",
    "otherIndustry": "aaaaaaaaaaaaa",
    "currentOrganization": "test",
    "salary": "1234567"
  };

myObject.currentIndustry = undefined;
myObject = JSON.parse(JSON.stringify(myObject));

console.log(myObject);

With es6 spread Operator:

const myObject = {
    "employeeid": "160915848",
    "firstName": "tet",
    "lastName": "test",
    "email": "[email protected]",
    "country": "Brasil",
    "currentIndustry": "aaaaaaaaaaaaa",
    "otherIndustry": "aaaaaaaaaaaaa",
    "currentOrganization": "test",
    "salary": "1234567"
};


const {currentIndustry, ...filteredObject} = myObject;
console.log(filteredObject);

Or if you can use omit() of underscore js library:

const filteredObject = _.omit(currentIndustry, 'myObject');
console.log(filteredObject);

When to use what??

If you don't wanna create a new filtered object, simply go for either option 1 or 2. Make sure you define your object with let while going with the second option as we are overriding the values. Or else you can use any of them.

hope this helps :)

Hassan Imam · Accepted Answer · 2017-10-06 06:42:51Z

8

Follow this, it can be like what you are looking:

var obj = {
    Objone: 'one',
    Objtwo: 'two'
};

var key = "Objone";
delete obj[key];
console.log(obj); // prints { "objtwo": two}

edited Oct 6, 2017 at 6:42

Hassan Imam

22.6k6 gold badges45 silver badges53 bronze badges

answered Oct 6, 2017 at 6:41

Muayyad Ayesh

1222 bronze badges

Comments

Penny Liu · Accepted Answer · 2018-10-04 07:20:11Z

2

Here is one more example. (check the reference)

const myObject = {
  "employeeid": "160915848",
  "firstName": "tet",
  "lastName": "test",
  "email": "[email protected]",
  "country": "Brasil",
  "currentIndustry": "aaaaaaaaaaaaa",
  "otherIndustry": "aaaaaaaaaaaaa",
  "currentOrganization": "test",
  "salary": "1234567"
};
const {otherIndustry, ...otherIndustry2} = myObject;
console.log(otherIndustry2);

.as-console-wrapper {
  max-height: 100% !important;
  top: 0;
}

answered Oct 4, 2018 at 7:20

Penny Liu

18k5 gold badges89 silver badges109 bronze badges

Comments

sachinkondana · Accepted Answer · 2020-11-12 11:05:41Z

2

function omit(obj, key) {
    const {[key]:ignore, ...rest} = obj;
    return rest;
}

You can use ES6 spread operators like this. And to remove your key simply call

const newJson = omit(myjsonobj, "otherIndustry");

Its always better if you maintain pure function when you deal with type=object in javascript.

answered Nov 12, 2020 at 11:05

sachinkondana

6916 silver badges15 bronze badges

Comments

Nick Gooch · Accepted Answer · 2019-08-26 15:12:33Z

0

I had issues with trying to delete a returned JSON object and found that it was actually a string. If you JSON.parse() before deleting you can be sure your key will get deleted.

let obj;
console.log(this.getBody()); // {"AED":3.6729,"AZN":1.69805,"BRL":4.0851}
obj = this.getBody();
delete obj["BRL"];
console.log(obj) // {"AED":3.6729,"AZN":1.69805,"BRL":4.0851}
obj = JSON.parse(this.getBody());
delete obj["BRL"];
console.log(obj) // {"AED":3.6729,"AZN":1.69805}

answered Aug 26, 2019 at 15:12

Nick Gooch

1

Comments

Nikolaos Ktistakis · Accepted Answer · 2024-07-04 21:46:26Z

0

In case you want to reassign a value (or 2 values) you can use @Mohammed Amir Ansari's answer and modify it a bit like this:

const myCarObject= { manufacturer: 'BMW',model: "M4", hp:503  };
const { model, hp, ...manufacturer} = myCarObject;
console.log(manufacturer)
//OUTPUT:
//{ manufacturer: 'BMW'}

console.log(model)
//OUTPUT:
//"M4"

console.log(hp)
//OUTPUT:
//503

This will extract the values from the car object and assign them to the other variables.

A bit late to the party, hope it will help someone.

answered Jul 4, 2024 at 21:46

Nikolaos Ktistakis

111 silver badge5 bronze badges

Collectives™ on Stack Overflow

how to remove json object key and value.?

7 Answers 7

2 Comments

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

7 Answers 7

2 Comments

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related