How to create a list without using range in Python (For Loops)?

Question

Let's say I have

myString = "ORANGE"

How can I write a for-each loop that lists each character so it looks like this

1O
2R
3A
4N
5G
6E

I am confused as I don't know how to do it without using range.

"But as a list so everything goes down vertically and not across." => ??? Sorry but I don't understand what you mean... — bruno desthuilliers
– bruno desthuilliers, Commented Oct 6, 2017 at 15:27

Xantium · Accepted Answer · 2017-10-07 21:48:14Z

2

This is quite basic. 5 answers and none of them actually say this I am surprised. Never mind this should do what you asked for:

myString = "ORANGE"
a = 1

for i in myString:

    print(str(a) + i)
    a = a + 1

answered Oct 7, 2017 at 21:48

Xantium

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Transhuman · Accepted Answer · 2017-10-06 15:26:14Z

1

myString = "ORANGE"
l = [str(i)+j for i,j in enumerate(myString,1)]
' '.join(l)

Output:

'1O 2R 3A 4N 5G 6E'

answered Oct 6, 2017 at 15:26

Transhuman

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Comments

blakev · Accepted Answer · 2017-10-06 15:32:27Z

1

for index, character in enumerate('ORANGE'):
    print('{}{}'.format(index + 1, character))

Python docs on enumerate

answered Oct 6, 2017 at 15:32

blakev

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Rohit-Pandey · Accepted Answer · 2017-10-08 06:27:51Z

1

Simple way to do this:

myString = "ORANGE"
for i in range(0,len(myString)):
    print (str(i+1)+""+myString[i])

Without using range:

myString = "ORANGE"
j=1
for i in myString:
    print (str(j)+""+i)
    j+=1

edited Oct 8, 2017 at 6:27

answered Oct 6, 2017 at 16:06

Rohit-Pandey

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Comments

imk · Accepted Answer · 2018-09-10 04:11:44Z

0

try this

myString = "ORANGE"
for id, val in enumerate(myString, 1):
    print("".join(str(id) + val))

edited Sep 10, 2018 at 4:11

answered Oct 6, 2017 at 15:49

imk

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