Node.js External function calling

Question

So I've been using NodeJS but I have a heavy background on C and C++, and I would like to know how would I "simulate" the header effect on NodeJS.

I have the following code

foo.js

 var Discord = require("discord.js");
    var request = require('request');
    var http = require('http');
    var express = require('express');
    var util = require('./dead.js');

util.beef()

then inside the other .js file

dead.js

exports.module = {
beef: function(){ request(something) }
}

I'm trying to make use of the request variable before declared inside foo.js, but it won't work because Node says it doesn't exist (so, ok it went out of scope)

Do I have to require every file I want to use in dead.js?
Would using require impact the performance too much?
When is it preferable to have a long single js file rather than have multiple ones and require in each one

SLaks · Accepted Answer · 2017-10-10 14:27:20Z

1

You need to require() every file every time you use it.

You cannot share variables directly across files, and this is a good thing (it prevents conflicts).

require() caches everything, so there are no performance concerns.

You should not put everything in a single giant JS file; that would be hard to maintain.

answered Oct 10, 2017 at 14:27

SLaks

891k182 gold badges1.9k silver badges2k bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Node.js External function calling

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related