Python code ignoring if statements

Question

In the process of writing an app, I've come across a bizarre python code piece that I can't understand:

The Code:

msg = [108878, [[314.06, 2, 4.744018], [314.03, 1, 15.9059], [314.02, 2, 79.8338531], [314, 1, 54.90047253], [313.56, 2, 1.75392219], [313.53, 2, 15.61132219], [313.5, 1, 0.554316], [313.42, 1, 1.5976], [313.27, 1, 0.43344], [313.26, 1, 62.724], [313.25, 1, 2.57518855], [313.24, 1, 0.04], [313.09, 2, 22.51784808], [312.9, 1, 40], [312.82, 1, 26.65592034], [312.7, 1, 35.53791008], [312.62, 1, 0.46912], [312.61, 1, 100], [312.6, 1, 48.33502123], [312.57, 1, 4.24547326], [312.56, 2, 0.2], [312.5, 2, 109.76863639], [312.43, 1, 100], [312.42, 1, 0.11142352], [312.4, 1, 7.815571], [314.09, 2, -3.01187461], [314.14, 1, -1.27056771], [314.39, 2, -9.31898324], [314.46, 1, -0.01930229], [314.49, 1, -0.40344], [314.5, 1, -3.40637161], [314.53, 1, -0.2], [314.54, 2, -0.46432889], [314.57, 1, -0.04200538], [314.71, 1, -0.050949], [314.84, 1, -0.02153813], [314.88, 1, -0.04200538], [314.93, 1, -68.439], [314.94, 2, -7.477782], [314.95, 1, -5], [315.1, 1, -5.97], [315.12, 1, -0.01], [315.16, 1, -40], [315.2, 1, -0.04200538], [315.22, 1, -25.7525], [315.23, 1, -78.54523718], [315.38, 1, -80], [315.42, 1, -6.65060488], [315.47, 1, -20], [315.48, 1, -5.36]]]

bids = asks = {}
lenbids = lenasks = 0
for order in msg[1]:
    if float(order[2])>0:
        lenbids +=1
        bids[order[0]]=order[2]
    elif float(order[2])<0:
        lenasks+=1
        asks[order[0]]=-order[2]

print(len(bids),len(asks),lenbids,lenasks)

Output:

50 50 25 25

It seems to me as though python is behaving properly with regards to the lenbids/lenasks actions but is executing the second part of the if statement regardless of whether the condition is met or not?

I'm running Pycharm with Anaconda3 if that makes any difference.

Any help greatly appreciated!

If statements work fine... The dictionaries are the exact same object. — OneCricketeer
– OneCricketeer, Commented Oct 18, 2017 at 0:41

donkopotamus · Accepted Answer · 2017-10-18 00:40:43Z

2

You have set bids and asks to be the same dictionary:

bids = asks = {}

You want them to be different dictionaries

bids, asks = {}, {}

answered Oct 18, 2017 at 0:40

donkopotamus

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2 Comments

BlindDev Over a year ago

Thanks donkopotamus! I often do things like a=b=0 to initialise variables and never had any issues with that....didn't know you couldn't do that with objects

Lawrence D'Oliveiro Over a year ago

Everything in Python is an object, including integers. But integers are not mutable objects (modifiable in-place), while dictionaries are.

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