Select random array variable name in bash

Question

#!/bin/bash

_0=("Mami"  "Bebe"  "Princesa"  "Mami")
_1=("Yo quiero " "Yo puedo "  "Yo vengo a " "Voy a ")
_2=("Encenderte"  "Amarte"  "Ligar"  "Jugar")
_3=("Suave"  "Lento"  "Rapido"  "Fuerte")
_4=("Hasta que salga el sol " "Toda la noche "  "Hasta el amanecer "  "Todo el dia ")
_5=("Sin anestecia " "Sin compromiso " "Feis to feis " "Sin Miedo ")

b=$(( $RANDOM % 6 ))

echo _$b[@]

I want to select randomly one array and print its value.

Why not use a case statement?

codeforester
– codeforester

2017-10-29 01:25:30 +00:00
Commented Oct 29, 2017 at 1:25 — codeforester
– codeforester, Commented Oct 29, 2017 at 1:25

Vasan · Accepted Answer · 2017-10-29 01:39:54Z

1

Please see this answer. Adapting it to your script, the last two lines become:

b=_$(( $RANDOM % 6 ))[@]
echo ${!b}

answered Oct 29, 2017 at 1:39

Vasan

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2 Comments

Eduardo Espinal Over a year ago

Thanks Vasan, It was what I really wanted

Eduardo Espinal Over a year ago

Mr vasan i use too: c=$(( $RANDOM % 4 )) b=_$(( $RANDOM % 6 ))[c] echo ${!b}

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