Calling of move constructor in c++

Question

I have following code:

struct Base
{
    std::vector<int> a;
}

struct Derived : public Base
{
    Derived(Base && rhs):
        Base( std::forward<Base>(rhs))
    {
    }
    //some more fields
}
//...
Base a;
Derived b(std::move(a));

Does calling of Derived constructor will lead calling of move constructor of std::vector that contained in Base class?

Yes, construction process of Base part of Derived object will invoke implicitly defined move c'tor of Base which will invoke move constructors of all the data members of Base. — sameerkn
– sameerkn, Commented Nov 1, 2017 at 6:30
You should use std::move here. std::forward is for forwarding arguments passed to templated functions. — Michaël Roy
– Michaël Roy, Commented Nov 1, 2017 at 10:17

songyuanyao · Accepted Answer · 2017-11-01 06:38:51Z

3

Yes, the implicitly-defined move constructor of Base is called, it will perform move on its data member a.

For non-union class types (class and struct), the move constructor performs full member-wise move of the object's bases and non-static members, in their initialization order, using direct initialization with an xvalue argument.

LIVE for confirming

edited Nov 1, 2017 at 6:38

answered Nov 1, 2017 at 6:21

songyuanyao

174k16 gold badges327 silver badges432 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Calling of move constructor in c++

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related