I need to loop over a number of files with structured files names.
They are of the form 'Mar00.sav', 'Sep00.sav', 'Mar01.sav'
At the moment I do this;
Years = ['01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15', '16', '17']
Which works but I was wondering if there is a better way?
I tried range but str(range(00,17)) will drop the leading zeros...
I had the same issue and there is a perfect solution to it -zfill method
An example of usage:
>>> str('1').zfill(7)
'0000001'
What you need to do is to create a generator for N numbers and fill its string representation with zeros.
>>> for i in range(1, 18):
... str(i).zfill(2)
...
'01'
'02'
'03'
...
'16'
'17'
>>> [str(i).zfill(2) for i in range(1,18)]
['01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15', '16', '17']
In python 2.7 , you can achieve it like this
>>> ["%02d" %i for i in range(0,17)]
['00', '01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15', '16']
>>>
if you want to print
>>> for i in range(00,17):
print '%02d' %i
00
01
02
03
04
05
06
07
08
09
10
11
12
13
14
15
16
>>>
["{:02}".format(n) for n in range(17)]In Python 3 you can use f string:
>>>[f"{i:02d}" for i in range(0,17)]
['00', '01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15', '16']
