Parsing plain text to js array - add separator to the second element

Question

I'm searching solution how to parse plain text to the js array. I have already found some scheme in which i want to do this, but kind of stuck.

Part of plain text:

2017-11-08 09:43:49,153 [INFO ] root: {\"methodId\":6,\"requestBody\":{},\"token\":\"XXXX\"}2017-11-08 09:53:02,293 [INFO ] root: {\"methodId\":6,\"requestBody\":{},\"token\":\"XXXX\"}2017-11-08 09:53:02,355 [INFO ] root: {\"methodId\":6,\"requestBody\":{},\"token\":\"XXXX\"}

Expected result

const arr = [
    '2017-11-08 09:43:49,153 [INFO ] root: {\"methodId\":6,\"requestBody\":{},\"token\":\"XXXX\"}',
    '2017-11-08 09:53:02,293 [INFO ] root: {\"methodId\":6,\"requestBody\":{},\"token\":\"XXXX\"}',
    '2017-11-08 09:53:02,355 [INFO ] root: {\"methodId\":6,\"requestBody\":{},\"token\":\"XXXX\"}'
]

RegEx Pattern:

/}\d{4}-\d{2}/

Each chunk ends by closing object "}" and starting new date "YYYY-MM".

Problem

plainText.split(/}\d{4}-\d{2}/)

If i split it this way, it always "eats" my separator. Is there some way to split text and add founded separator to the second element from the splited pair? Then i could just add "}" to the first one and remove "}" from the second one. It's solution I'm thinking about, but maybe you can suggest something even better.

Where does this messed up plain text come from in the first place? — melpomene
– melpomene, Commented Nov 8, 2017 at 9:56
s.split(/\b(?=\d{4}-\d{2}-\d{2}\s+[\d:,]+\s+\[INFO ]\s+root:)/).filter(Boolean). Shorten the pattern if the requirements can be lax (depends on the scenario, it can even be /\b(?=\d{4}-\d{2}-\d{2}\s/ if the date strings do not appear in the JSON data). See this demo. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Nov 8, 2017 at 10:00
@melpomene It's response from the api I'm working with. I have no control over the form in which it gets the answer. — Dan Zawadzki
– Dan Zawadzki, Commented Nov 8, 2017 at 10:02

Wiktor Stribiżew · Accepted Answer · 2017-11-08 10:16:17Z

1

If the JSON data does not contain datetime-like substrings, you may use

s.split(/\b(?=\d{4}-\d{2}-\d{2}\s/).filter(Boolean)

Or a more verbose (to play it safer):

s.split(/\b(?=\d{4}-\d{2}-\d{2}\s+[\d:,]+\s+\[INFO ]\s+root:)/).filter(Boolean)

See the regex demo

The point is to match the datetime-like string but not consume it, thus, the whole pattern is wrapped within a positive lookahead (?=...) construct.

Longer pattern details

\b - a word boundary
(?= - start of the positive lookahead pattern
- \d{4}-\d{2}-\d{2} - date-like string (4 digits-2 digits-2 digits)
- \s+ - 1 or more whitespaces
- [\d:,]+ - 1 or more digits, : or/and ,
- \s+ - 1 or more whitespaces
- \[INFO ] - an [INFO ] substring
- \s+ - 1+ whitespaces
- root: - root: substring
) - end of the lookahead

edited Nov 8, 2017 at 10:16

answered Nov 8, 2017 at 10:14

Wiktor Stribiżew

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