Passing variable length list as an argument to threaded function

Question

I'm trying to pass a list as an argument to a threaded function. This list can vary in it's length, but I can't figure out how to do it. Below is the code I'm using. For now, I just want to be able to get the list into the threaded function and print it on-screen.

#!/usr/bin/python
import threading
import Queue as queue


def generateRange(starting_chars=(*args)):
    print str(starting_chars)


for i in range(32,126):
    q = queue.Queue()
    theArgs = [i,32,32]
    threads = [ threading.Thread(target=generateRange,args=theArgs) ]
    # generateRange([i,32,32]) 
    for th in threads:
        th.daemon = True
        th.start()

I'm getting this error:

    File "./test.py", line 6
    def generateRange(starting_chars=(*args)):
                                      ^
SyntaxError: invalid syntax

What am I doing wrong?

PRMoureu · Accepted Answer · 2017-11-11 08:11:06Z

1

You can change the syntax to this, otherwise args will not be defined:

def generateRange(*starting_chars):
    print str(starting_chars)

answered Nov 11, 2017 at 8:11

PRMoureu

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Comments

Edgardo Gutierrez · Accepted Answer · 2017-11-11 08:11:31Z

1

I don't know why you specifically want the argument to be named 'starting_chars' but:

def generateRange(*starting_chars):
    print str(starting_chars)

or

def generateRange(*args):
    print str(args)

should work fine

answered Nov 11, 2017 at 8:11

Edgardo Gutierrez

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