JS split regex by two different character

Question

I have 2 strings:

"test:header_footer"
"test_3142"

I want to get array:

array = "test:header_footer".split(":") // ['test', 'header_footer']
array2 = "test_3142".split("_") // ['test', '3142']

Can I combine this with a regex expression to get the same result?

function(s) {
 retutn s.split(/:|_/) // return bad value
}

So if string contain ':' - not separate by second '_'

Your conditions are not regular, therefore regular expressions are a poor fit. Instead, first determine if a : is present, and then choose the split character accordingly. — Niet the Dark Absol
– Niet the Dark Absol, Commented Nov 13, 2017 at 13:33
your first string contains both : and _, how do you decide which one is the delimiter? — Yossi Vainshtein
– Yossi Vainshtein, Commented Nov 13, 2017 at 13:44

Razzildinho · Accepted Answer · 2017-11-13 13:44:59Z

1

You could write a one line method to check for : and split based on that condition.

var text = "your:string";
var array = text.split(text.indexOf(":") >= 0 ? ":" : "_"); // ['your', 'string']

var text2 = "your_string";
var array2 = text.split(text.indexOf(":") >= 0 ? ":" : "_"); // ['your', 'string']

var text3 = "your:other_string";
var array3 = text.split(text.indexOf(":") >= 0 ? ":" : "_"); // ['your', 'other_string']

This will check for :, if that is found then split by :, otherwise split by _.

answered Nov 13, 2017 at 13:44

Razzildinho

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zfrisch · Accepted Answer · 2017-11-13 16:59:14Z

0

You can use the includes method on your String to determine if there's a : present. If there is split the String by the colon, otherwise split the String by the underscore.

split_string = s => s.includes(":") ? s.split(":") : s.split("_");

//test strings
let str = "my:string_demo",
  str2 = "my_string_demo",
  str3 = "myString:demo_thing",
  //string function
  split_string = s => s.includes(":") ? s.split(":") : s.split("_");


console.log(
  str, split_string(str)
);
console.log(
  str2, split_string(str2)
);
console.log(
  str3, split_string(str3)
);

answered Nov 13, 2017 at 16:59

zfrisch

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