Inserting a php variable in background-image

Question

I'm trying to build a widget for a website that displays a random background image everytime the page is refreshed and i'm running into some trouble with string concatenation.

$display .= "<p class=\"ey-image-quote\" style\"background-image:url('".$img."')\">" . $this->quote . "</p>";

This returns a url without slashes (replaced by spaces) and i have not found a viable solution yet. Is there any way to achieve this in php?

Surely you don't want the backslashes? All the blackslashes do is allow you to use " in your html. 3v4l.org/rRm1Z . As @ProEvilz said, you're missing the = after style and then it should work — IsThisJavascript
– IsThisJavascript, Commented Nov 16, 2017 at 12:42

pr1nc3 · Accepted Answer · 2017-11-16 12:41:57Z

3

$display .= "<p class=\"ey-image-quote\" style=\"background-image:url('".$img."')\">" . $this->quote . "</p>";

You forgot = in style

answered Nov 16, 2017 at 12:41

pr1nc3

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