Python list editing

Question

I have to make a program that asks for the "login hour" 24 times, puts all those values into a list and then outputs how many times each login hour was used and if you type -1 it breaks the loop for example with 6 inputs it would be.

Please enter login hour: 3
Please enter login hour: 4
Please enter login hour: 3
Please enter login hour: 3
Please enter login hour: 4
Please enter login hour: -1
There were 0 logins In hour 0
There were 0 logins In hour 1
There were 0 logins In hour 2 
There were 3 logins In hour 3
There were 2 logins In hour 4
....till 24

This is what I have done so far. I just do not know how to count each element type and make them separate from the rest.

loginCount = 0
hour = []
for i in range(0,24):
     item = int(input("please enter login hour:")
     hour.append(item)
     if hour[i] == -1
          break
     else: 
          loginCount = loginCount + 1

Eugen Konkov · Accepted Answer · 2017-11-22 08:54:57Z

1

You can use a fixed size array and up count appropriate index each time: It is hour[item-1] since list indexing starts at 0.

hour = [0] * 24
for i in range(0,24):
   item = int(input("please enter login hour: "))
   if item == -1:
      break
   else:
      hour[item] += 1

edited Nov 22, 2017 at 8:54

Eugen Konkov

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answered Nov 21, 2017 at 10:13

NaWeeD

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Comments

Saurabh Mithe · Accepted Answer · 2017-11-21 10:56:32Z

0

# We will maintain a list with 24 entries
# Each entry in the list will maintain a count for the number
# of logins in that hour. Finally, we will print all the entries
# from the list that will output number of logins for each hour

# Creating a list with one entry for each hour
records = [0] * 24

# Asking user 24 times
for j in range(0, 24):
    i = int(input("please enter login hour:"))
    # Since lists are mutable, we can increment the count 
    # at the corresponding position of the input hour
    if i != -1:
        records[i - 1] = records[i - 1] + 1
    else:
        break

# Print all the entries from the records
for i in range(len(records)):
    print("There were " + str(records[i]) + " logins in hour " + str(i+1))

edited Nov 21, 2017 at 10:56

answered Nov 21, 2017 at 10:38

Saurabh Mithe

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Comments

Abhijeetk431 · Accepted Answer · 2017-11-21 10:56:53Z

0

I have added a while loop to count the number of elements in the list. Hope you do not want to add -1 to the list. Included if statement to not append -1 and break when user inputs -1 Before the second loop, I have created another list which will contain unique values from hour to print number of attempts for only those numbers for whom attempt has actually been made(this is slightly different from what you have mentioned in question, You can get that be changing sorted(unique_hrs) in second loop to range(1,25)).

hour = []
while len(hour) < 24:
    item = int(input("please enter login hour: "))
    if item != -1:
        hour.append(item)
    else:
        break

unique_hrs = list(set(hour))
for i in sorted(unique_hrs):
    print('There were ' + str(hour.count(i)) + ' logins In hour ' + str(i))

edited Nov 21, 2017 at 10:56

answered Nov 21, 2017 at 10:29

Abhijeetk431

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1 Comment

Abhijeetk431 Over a year ago

It was my bad. I did not realize it wont help OP. I just copied and pasted the working code without explaining what I am doing here.

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