I am not sure why I am getting an extra comma at the end of every output when using the Match() with Regex in python. Any ideas ? Thanks.
My Code:
import re
yyyyfile = open("yyyy.txt",'w')
text = open('final.txt')
for line in text:
x = re.match('.*?^([0-9][0-9][0-9][0-9])$.*', line)
if x:
print >> yyyyfile, x.groups()
Current Output:
('1573',)
('1595',)
('1929',)
('1933',)
Desired Output:
('1573')
('1595')
('1929')
('1933')
It's because the output of re.match's groups() is all of the groups that you captured. It's a tuple.
Use x.group(1) or whatever instead.
You are not getting an extra comma because you using match. The reason you get this comma is that you are printing out tuples. You can achieve the desired result like this
print >> yyyyfile, '(%s)' % x.group(1)
I don't know what is inside yyyy.txt and why you want to print it but assuming final.txt includes the text you should open the file with:
with open('final.txt', 'r') as f:
text = f.read()
parsing works like this:
import re
text = '''1235, dfx as nxcn 1229 nxcn 32 4 0 9877'''
matches = re.findall('(\d{4})', text)
for match in matches:
print(match)
