regex to match 3 parts from a given string

Question

Example input:

hjkhwe5boijdfg

I need to split this into 3 variables as below:

hjkhwe5 (any length, always ends in some number (can be any number))
b (always a single letter, can be any letter)
oijdfg (everything remaining at the end, numbers or letters in any combination)

I've got the PHP preg_match all setup but have no idea how to do this complex regex. Could someone give me a hand?

Toto · Accepted Answer · 2011-01-20 11:25:01Z

1

Have a try with:

$str = 'hjkhwe5boijdfg';
preg_match("/^([a-z]+\d+)([a-z])(.*)$/", $str, $m);
print_r($m);

output:

Array
(
    [0] => hjkhwe5boijdfg
    [1] => hjkhwe5
    [2] => b
    [3] => oijdfg
)

Explanation:

^           : begining of line
  (         : 1rst group
    [a-z]+  : 1 or more letters
    \d+     : followed by 1 or more digit
  )         : end of group 1
  (         : 2nd group
    [a-z]   : 1 letter
  )         : end group 2
  (         : 3rd group
    .*      : any number of any char
  )         : end group 3
$

answered Jan 20, 2011 at 11:25

Toto

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1 Comment

David19801 Over a year ago

Coda was faster, but that explanation just nailed it. I now understand regex! Thank you :)

codaddict · Accepted Answer · 2011-01-20 11:18:10Z

0

You can use preg_match as:

$str = 'hjkhwe5boijdfg';
if(preg_match('/^(\D*\d+)(\w)(.*)$/',$str,$m)) {
        // $m[1] has part 1, $m[2] has part 2 and $m[3] has part 3.
}

See it

answered Jan 20, 2011 at 11:18

codaddict

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